Short Answer
The horizontal coordinates of a Frisbee™ in a strong wind are given by x = -12t + 4t2 and
y = 10t - 3t2, where x and y are in meters, and t is in seconds.
(a) What is the acceleration of the Frisbee? Give a magnitude and a direction, measuring angles from the positive x direction.
(b) What is the magnitude of the velocity at t = 2.0 s, accurate to the nearest m/s?
Correct Answer:

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(a) 10 m/s...View Answer
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