Short Answer
The excited state of a certain atom is 3.2 eV ± 0.21 eV. ( = 1.055 × 10-34 J ∙ s = 6.591 × 10-16 eV ∙ s, 1 eV = 1.60 × 10-19 J)
(a) What is the average lifetime of this state?
(b) If the excited energy were doubled to 6.4 eV ± 0.21 eV, how would the lifetime be affected?
Correct Answer:

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(a) 0.78 fs
(b) unc...View Answer
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Correct Answer:
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(b) unc...
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