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In the Standard Model of the Expansion of the Universe,the ρc=H28πG\rho _ { c } = \frac { H ^ { 2 } } { 8 \pi G }

Question 20

Multiple Choice

In the standard model of the expansion of the universe,the total energy of a standard mass m is assumed to be zero.When we solve the resulting energy equation for the critical mass density of the universe,we find that the critical mass density is given by


A) ρc=H28πG\rho _ { c } = \frac { H ^ { 2 } } { 8 \pi G } .
B) ρc=3H28πG\rho _ { c } = \frac { 3 H ^ { 2 } } { 8 \pi G } .
C) ρc=3H22πG\rho _ { c } = \frac { 3 H ^ { 2 } } { 2 \pi G } .
D) ρc=3H2πG\rho _ { c } = \frac { 3 H ^ { 2 } } { \pi G } .
E) ρc=3H2G\rho _ { c } = \frac { 3 H ^ { 2 } } { G } .

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