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In an Electromagnetic Wave,1)how Are the Electric and Magnetic Field c\overrightarrow { \mathbf { c } }

Question 4

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In an electromagnetic wave,1) how are the electric and magnetic field directions related and 2) how is the direction of travel determined from their directions? ( c\overrightarrow { \mathbf { c } } is the velocity of the light wave. )


A) EB;cc=E×BE×B\overrightarrow { \mathbf { E } } \| \overrightarrow { \mathbf { B } } ; \frac { \overrightarrow { \mathbf { c } } } { c } = \frac { \overrightarrow { \mathbf { E } } \times \overrightarrow { \mathbf { B } } } { | \overrightarrow { \mathbf { E } } \times \overrightarrow { \mathbf { B } } | } .
B) EB;cc=B×EB×E\overrightarrow { \mathbf { E } } \| \overrightarrow { \mathbf { B } } ; \frac { \overrightarrow { \mathbf { c } } } { c } = \frac { \overrightarrow { \mathbf { B } } \times \overrightarrow { \mathbf { E } } } { | \overrightarrow { \mathbf { B } } \times \overrightarrow { \mathbf { E } } | } .
C) EB;cc=E×BE×B\overrightarrow { \mathbf { E } } \perp \overrightarrow { \mathbf { B } } ; \frac { \overrightarrow { \mathbf { c } } } { c } = \frac { \overrightarrow { \mathbf { E } } \times \overrightarrow { \mathbf { B } } } { | \overrightarrow { \mathbf { E } } \times \overrightarrow { \mathbf { B } } | } .
D) EB;cc=B×EB×E\overrightarrow { \mathbf { E } } \perp \overrightarrow { \mathbf { B } } ; \frac { \overrightarrow { \mathbf { c } } } { c } = \frac { \overrightarrow { \mathbf { B } } \times \overrightarrow { \mathbf { E } } } { | \overrightarrow { \mathbf { B } } \times \overrightarrow { \mathbf { E } } | } .
E) E=B/c;cc=B×EB×E\overrightarrow { \mathbf { E } } = \overrightarrow { \mathbf { B } } / c ; \frac { \overrightarrow { \mathbf { c } } } { c } = \frac { \overrightarrow { \mathbf { B } } \overrightarrow { \times } \mathbf { E } } { | \overrightarrow { \mathbf { B } } \times \overrightarrow { \mathbf { E } } | } .

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