The Nucleus of Lead-208 ${ } _ { 82 } ^ { 208 } \mathrm {~Pb}$

Short Answer

The nucleus of lead-208, ${ } _ { 82 } ^ { 208 } \mathrm {~Pb}$ ,has 82 protons within a sphere of radius 6.34 *10 ^{- 15}.Each electric charge has a value of 1.60 *10 ^{- 19} C.Assuming that the protons create a spherically symmetric distribution of charge,calculate the electric field at the surface of the nucleus.