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A 30-Kg Particle Has a Position Vector Given By By \overrightarrow

Question 56

Multiple Choice

A 3.0-kg particle has a position vector given by r=(2.0t2i^+3.0j^) \overrightarrow { \mathbf { r } } = \left( 2.0 t ^ { 2 } \hat { \mathbf { i } } + 3.0 \hat { \mathbf { j } } \right) where r\overrightarrow { \mathbf { r } } is in meters and t is in seconds.What is the angular momentum of the particle,in kg.m2/s,about the origin at t = 2 s?


A) 72 k^\hat { k }
B) -72 k^\hat { k }
C) 24 k^\hat { k }
D) -24 k^\hat { k }
E) 22 k^\hat { k }

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