A compound with the molecular formula C₁₈H₁₈O₄ has a ¹H NMR spectrum that consists of: singlet,

\delta

2.7
Singlet,

\delta

3.1
Multiplet,

\delta

7.3
The IR spectrum shows a strong absorption band near 1750 cm^-1.The most likely structure for the compound is:
A)
$A compound with the molecular formula C18H18O4 has a 1H NMR spectrum that consists of: singlet, \delta 2.7 Singlet, \delta 3.1 Multiplet, \delta 7.3 The IR spectrum shows a strong absorption band near 1750 cm-1.The most likely structure for the compound is: A) B) C) D) E)$
B)
$A compound with the molecular formula C18H18O4 has a 1H NMR spectrum that consists of: singlet, \delta 2.7 Singlet, \delta 3.1 Multiplet, \delta 7.3 The IR spectrum shows a strong absorption band near 1750 cm-1.The most likely structure for the compound is: A) B) C) D) E)$
C)
$A compound with the molecular formula C18H18O4 has a 1H NMR spectrum that consists of: singlet, \delta 2.7 Singlet, \delta 3.1 Multiplet, \delta 7.3 The IR spectrum shows a strong absorption band near 1750 cm-1.The most likely structure for the compound is: A) B) C) D) E)$
D)
$A compound with the molecular formula C18H18O4 has a 1H NMR spectrum that consists of: singlet, \delta 2.7 Singlet, \delta 3.1 Multiplet, \delta 7.3 The IR spectrum shows a strong absorption band near 1750 cm-1.The most likely structure for the compound is: A) B) C) D) E)$
E)
$A compound with the molecular formula C18H18O4 has a 1H NMR spectrum that consists of: singlet, \delta 2.7 Singlet, \delta 3.1 Multiplet, \delta 7.3 The IR spectrum shows a strong absorption band near 1750 cm-1.The most likely structure for the compound is: A) B) C) D) E)$

Which Carboxylic Acid Would Decarboxylate When Heated to 100-150 °\degree° C? A) I B) II C) III D) More

Multiple Choice

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

Which Carboxylic Acid Would Decarboxylate When Heated to 100-150 $\degree$ C?
A) I
B) II
C) III
D) More

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge