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Find Pk+1 for the Given Pk pk=k27(k+2)2p _ { k } = \frac { k ^ { 2 } } { 7 ( k + 2 ) ^ { 2 } }

Question 29

Multiple Choice

Find pk+1 for the given pk.? pk=k27(k+2) 2p _ { k } = \frac { k ^ { 2 } } { 7 ( k + 2 ) ^ { 2 } } ?


A) pk+1=(k+1) 23(k+8) 2p _ { k + 1 } = \frac { ( k + 1 ) ^ { 2 } } { 3 ( k + 8 ) ^ { 2 } }
B) pk+1=(k+1) 28(k+8) 2p _ { k + 1 } = \frac { ( k + 1 ) ^ { 2 } } { 8 ( k + 8 ) ^ { 2 } }
C) pk+1=(k+1) 28(k+3) 2p _ { k + 1 } = \frac { ( k + 1 ) ^ { 2 } } { 8 ( k + 3 ) ^ { 2 } }
D) pk+1=(k+1) 27(k+3) 2p _ { k + 1 } = \frac { ( k + 1 ) ^ { 2 } } { 7 ( k + 3 ) ^ { 2 } }
E) pk+1=(k+1) 27(k+8) 2p _ { k + 1 } = \frac { ( k + 1 ) ^ { 2 } } { 7 ( k + 8 ) ^ { 2 } }

Correct Answer:

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