Find Pk +1 for the Given P k \[P _ { k } = \frac { 2 } { k ( k + 1 ) }\]

The Answer of Find Pk +1 for the Given P k \[P _ { k } = \frac { 2 } { k ( k + 1 ) }\]

Find Pk +1 for the Given P k \[P _ { k } = \frac { 2 } { k ( k + 1 ) }\]

The Answer of Find Pk +1 for the Given P k \[P _ { k } = \frac { 2 } { k ( k + 1 ) }\]

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Find Pk₊₁ for the Given P_k $P _ { k } = \frac { 2 } { k ( k + 1 ) }$

Question 18

Multiple Choice

Find Pk₊₁ for the given P_k. $P _ { k } = \frac { 2 } { k ( k + 1 ) }$

A) $P _ { k + 1 } = \frac { 2 } { k ( k + 2 ) }$
B) $P _ { k + 1 } = \frac { 2 } { k ( k + 1 ) } + \frac { 2 } { ( k + 1 ) ( k + 2 ) }$
C) $P _ { k + 1 } = \frac { 4 } { ( k + 1 ) ( k + 2 ) }$
D) $P _ { k + 1 } = \frac { 2 } { ( k + 1 ) ( k + 2 ) }$
E) $P _ { k + 1 } = \frac { 2 } { k ( k + 1 ) } + 1$

Find Pk+1 for the Given Pk Pk=2k(k+1)P _ { k } = \frac { 2 } { k ( k + 1 ) }Pk​=k(k+1)2​

Multiple Choice

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Find Pk₊₁ for the Given P_k $P _ { k } = \frac { 2 } { k ( k + 1 ) }$

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