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Find Pk+1 for the Given Pk Pk=3k(k+7)P _ { k } = \frac { 3 } { k ( k + 7 ) }

Question 25

Multiple Choice

Find Pk+1 for the given Pk. Pk=3k(k+7) P _ { k } = \frac { 3 } { k ( k + 7 ) }


A) Pk+1=3k(k+7) +1P _ { k + 1 } = \frac { 3 } { k ( k + 7 ) } + 1
B) Pk+1=3k(k+7) +3(k+1) (k+8) P _ { k + 1 } = \frac { 3 } { k ( k + 7 ) } + \frac { 3 } { ( k + 1 ) ( k + 8 ) }
C) Pk+1=3(k+1) (k+8) P _ { k + 1 } = \frac { 3 } { ( k + 1 ) ( k + 8 ) }
D) Pk+1=3k(k+8) P _ { k + 1 } = \frac { 3 } { k ( k + 8 ) }
E) Pk+1=8(k+1) (k+7) P _ { k + 1 } = \frac { 8 } { ( k + 1 ) ( k + 7 ) }

Correct Answer:

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