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Question 18
Find 6A. A=[1−11−1]A = \left[ \begin{array} { l l } 1 & - 1 \\1 & - 1\end{array} \right]A=[11−1−1]
A) [6−66−6]\left[ \begin{array} { l l } 6 & - 6 \\6 & - 6\end{array} \right][66−6−6] B) [8−66−6]\left[ \begin{array} { l l } 8 & - 6 \\6 & - 6\end{array} \right][86−6−6] C) [10−6−66]\left[ \begin{array} { c c } 10 & - 6 \\- 6 & 6\end{array} \right][10−6−66] D) [4−66−6]\left[ \begin{array} { l l } 4 & - 6 \\6 & - 6\end{array} \right][46−6−6] E) [2−66−6]\left[ \begin{array} { l l } 2 & - 6 \\6 & - 6\end{array} \right][26−6−6]
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