?Applying Kirchhoff's Laws to the Electrical Network in the Figure,the\[\left\{ \begin{array} { l l } I _ { 1 } - I _ { 2 } + I _ { 3 } & = 0 \\ 6 I _ { 1 } + 3 I _ { 2 } & = 11 \\ 3 I _ { 2 } + 5 I _ { 3 } & = 6 \end{array} \right.\]

The Answer of ?Applying Kirchhoff's Laws to the Electrical Network in the Figure,the\[\left\{ \begin{array} { l l } I _ { 1 } - I _ { 2 } + I _ { 3 } & = 0 \\ 6 I _ { 1 } + 3 I _ { 2 } & = 11 \\ 3 I _ { 2 } + 5 I _ { 3 } & = 6 \end{array} \right.\]

?Applying Kirchhoff's Laws to the Electrical Network in the Figure,the\[\left\{ \begin{array} { l l } I _ { 1 } - I _ { 2 } + I _ { 3 } & = 0 \\ 6 I _ { 1 } + 3 I _ { 2 } & = 11 \\ 3 I _ { 2 } + 5 I _ { 3 } & = 6 \end{array} \right.\]

The Answer of ?Applying Kirchhoff's Laws to the Electrical Network in the Figure,the\[\left\{ \begin{array} { l l } I _ { 1 } - I _ { 2 } + I _ { 3 } & = 0 \\ 6 I _ { 1 } + 3 I _ { 2 } & = 11 \\ 3 I _ { 2 } + 5 I _ { 3 } & = 6 \end{array} \right.\]

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?Applying Kirchhoff's Laws to the Electrical Network in the Figure,the

Question 52

Multiple Choice

?Applying Kirchhoff's Laws to the electrical network in the figure,the currents I₁,I₂,and I₃ are the solution of the system $\left\{ \begin{array} { l l } I _ { 1 } - I _ { 2 } + I _ { 3 } & = 0 \\6 I _ { 1 } + 3 I _ { 2 } & = 11 \\3 I _ { 2 } + 5 I _ { 3 } & = 6\end{array} \right.$ Find the currents.? $?Applying Kirchhoff's Laws to the electrical network in the figure,the currents I1,I2,and I3 are the solution of the system \left\{ \begin{array} { l l } I _ { 1 } - I _ { 2 } + I _ { 3 } & = 0 \\ 6 I _ { 1 } + 3 I _ { 2 } & = 11 \\ 3 I _ { 2 } + 5 I _ { 3 } & = 6 \end{array} \right. Find the currents.? \begin{array} { l } V _ { 1 } = 11 \text { volts, } V _ { 2 } = 6 \text { volts } \\ R _ { 1 } = 6 \Omega , R _ { 2 } = 3 \Omega , R _ { 3 } = 5 \Omega \end{array} ? A) ?I1 = - \frac { 40 } { 3 } amperes;I2 = \frac { 91 } { 3 } amperes;I3 = -17 amperes B) ?I1 = \frac { 10 } { 9 } amperes;I2 = \frac { 13 } { 9 } amperes;I3 = \frac { 1 } { 3 } amperes C) ?I1 = 6 amperes;I2 = 3 amperes;I3 = 5 amperes D) ?I1 = \frac { 70 } { 33 } amperes;I2 = - \frac { 19 } { 33 } amperes;I3 = \frac { 17 } { 11 } amperes E) ?I1 = 70 amperes;I2 = 91 amperes;I3 = 21 amperes$ $\begin{array} { l } V _ { 1 } = 11 \text { volts, } V _ { 2 } = 6 \text { volts } \\R _ { 1 } = 6 \Omega , R _ { 2 } = 3 \Omega , R _ { 3 } = 5 \Omega\end{array}$ ?

A) ?I₁ = $- \frac { 40 } { 3 }$ amperes;I₂= $\frac { 91 } { 3 }$ amperes;I₃ = -17 amperes
B) ?I₁ = $\frac { 10 } { 9 }$ amperes;I₂ = $\frac { 13 } { 9 }$ amperes;I₃ = $\frac { 1 } { 3 }$ amperes
C) ?I₁ = 6 amperes;I₂ = 3 amperes;I₃ = 5 amperes
D) ?I₁ = $\frac { 70 } { 33 }$ amperes;I₂ = $- \frac { 19 } { 33 }$ amperes;I₃ = $\frac { 17 } { 11 }$ amperes
E) ?I₁ = 70 amperes;I₂ = 91 amperes;I₃ = 21 amperes

?Applying Kirchhoff's Laws to the Electrical Network in the Figure,the

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