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Sixty Liters of a 43% Acid Solution Is Obtained by Mixing

Question 32

Multiple Choice

Sixty liters of a 43% acid solution is obtained by mixing a 28% solution with a 42% solution.Use a graphing utility to graph the two given equations.Let x and y represent the amounts of the 28 % solution and 42% solution.As the amount of the 28% solution increases,how does the amount of the 42% solution change? $\left\{ \begin{array} { l } x + y = 60 \\0.28 x + 0.42 y = 25.8\end{array} \right.$

A) $Sixty liters of a 43% acid solution is obtained by mixing a 28% solution with a 42% solution.Use a graphing utility to graph the two given equations.Let x and y represent the amounts of the 28 % solution and 42% solution.As the amount of the 28% solution increases,how does the amount of the 42% solution change? \left\{ \begin{array} { l } x + y = 60 \\ 0.28 x + 0.42 y = 25.8 \end{array} \right. A) Increases B) Decreases C) Decreases D) Decreases E) Increases$
Increases
B) $Sixty liters of a 43% acid solution is obtained by mixing a 28% solution with a 42% solution.Use a graphing utility to graph the two given equations.Let x and y represent the amounts of the 28 % solution and 42% solution.As the amount of the 28% solution increases,how does the amount of the 42% solution change? \left\{ \begin{array} { l } x + y = 60 \\ 0.28 x + 0.42 y = 25.8 \end{array} \right. A) Increases B) Decreases C) Decreases D) Decreases E) Increases$
Decreases
C) $Sixty liters of a 43% acid solution is obtained by mixing a 28% solution with a 42% solution.Use a graphing utility to graph the two given equations.Let x and y represent the amounts of the 28 % solution and 42% solution.As the amount of the 28% solution increases,how does the amount of the 42% solution change? \left\{ \begin{array} { l } x + y = 60 \\ 0.28 x + 0.42 y = 25.8 \end{array} \right. A) Increases B) Decreases C) Decreases D) Decreases E) Increases$
Decreases
D) $Sixty liters of a 43% acid solution is obtained by mixing a 28% solution with a 42% solution.Use a graphing utility to graph the two given equations.Let x and y represent the amounts of the 28 % solution and 42% solution.As the amount of the 28% solution increases,how does the amount of the 42% solution change? \left\{ \begin{array} { l } x + y = 60 \\ 0.28 x + 0.42 y = 25.8 \end{array} \right. A) Increases B) Decreases C) Decreases D) Decreases E) Increases$
Decreases
E) $Sixty liters of a 43% acid solution is obtained by mixing a 28% solution with a 42% solution.Use a graphing utility to graph the two given equations.Let x and y represent the amounts of the 28 % solution and 42% solution.As the amount of the 28% solution increases,how does the amount of the 42% solution change? \left\{ \begin{array} { l } x + y = 60 \\ 0.28 x + 0.42 y = 25.8 \end{array} \right. A) Increases B) Decreases C) Decreases D) Decreases E) Increases$
Increases

Sixty Liters of a 43% Acid Solution Is Obtained by Mixing

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