Solved

Find Values for B Such That the Triangle Has One b>16.2,b>16.2sin24b > 16.2 , b > \frac { 16.2 } { \sin 24 ^ { \circ } }

Question 12

Multiple Choice

Find values for b such that the triangle has one solution. ?
A = 24?°,a = 16.2
?


A) b>16.2,b>16.2sin24b > 16.2 , b > \frac { 16.2 } { \sin 24 ^ { \circ } }
B) b16.2,b=16.2sin24b \leq 16.2 , b = \frac { 16.2 } { \sin 24 ^ { \circ } }
C) b16.2,b16.2sin24b \leq 16.2 , b \neq \frac { 16.2 } { \sin 24 ^ { \circ } }
D) b16.2,b16.2sin24b \geq 16.2 , b \geq \frac { 16.2 } { \sin 24 ^ { \circ } }
E) b16.2,b=16.2sin24b \geq 16.2 , b = \frac { 16.2 } { \sin 24 ^ { \circ } }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions