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Find All Solutions of the Given Equation in the Interval 12sin2x=cosx\frac { 1 } { 2 } \sin 2 x = \cos x

Question 28

Multiple Choice

Find all solutions of the given equation in the interval [0,2π) . ​​ 12sin2x=cosx\frac { 1 } { 2 } \sin 2 x = \cos x


A) ​ x=π2,3π2x = \frac { \pi } { 2 } , \frac { 3 \pi } { 2 }
B) ​ x=0,π2,πx = 0 , \frac { \pi } { 2 } , \pi
C) ​ x=0,π,π2,3π4x = 0 , \pi , \frac { \pi } { 2 } , \frac { 3 \pi } { 4 }
D) ​ x=0,πx = 0 , \pi
E) ​x = 0

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