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Use the Change-Of-Base Formula to Rewrite the Logarithm as a Ratio

Question 47

Multiple Choice

Use the change-of-base formula to rewrite the logarithm as a ratio of logarithms.Then use a graphing utility to graph the ratio.
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F(x) = log11.7 x
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A) f(x) =logxlog11.7=lnxln11.7f ( x ) = \frac { \log x } { \log 11.7 } = \frac { \ln x } { \ln 11.7 }  Use the change-of-base formula to rewrite the logarithm as a ratio of logarithms.Then use a graphing utility to graph the ratio. ? F(x) = log<sub>11.7</sub> x ? A)   f ( x )  = \frac { \log x } { \log 11.7 } = \frac { \ln x } { \ln 11.7 }    B)   f ( x )  = \frac { \log 11.7 } { \log x } = \frac { \ln 11.7 } { \ln x }    C) f(x) = log x? + log 11.7 = ln x? + ln 11.7   D)   f ( x )  = \log \frac { 11.7 } { x } = \ln \frac { 11.7 } { x }    E)   f ( x )  = \log \frac { x } { 11.7 } = \ln \frac { x } { 11.7 }  ?
B) f(x) =log11.7logx=ln11.7lnxf ( x ) = \frac { \log 11.7 } { \log x } = \frac { \ln 11.7 } { \ln x }  Use the change-of-base formula to rewrite the logarithm as a ratio of logarithms.Then use a graphing utility to graph the ratio. ? F(x) = log<sub>11.7</sub> x ? A)   f ( x )  = \frac { \log x } { \log 11.7 } = \frac { \ln x } { \ln 11.7 }    B)   f ( x )  = \frac { \log 11.7 } { \log x } = \frac { \ln 11.7 } { \ln x }    C) f(x) = log x? + log 11.7 = ln x? + ln 11.7   D)   f ( x )  = \log \frac { 11.7 } { x } = \ln \frac { 11.7 } { x }    E)   f ( x )  = \log \frac { x } { 11.7 } = \ln \frac { x } { 11.7 }  ?
C) f(x) = log x? + log 11.7 = ln x? + ln 11.7  Use the change-of-base formula to rewrite the logarithm as a ratio of logarithms.Then use a graphing utility to graph the ratio. ? F(x) = log<sub>11.7</sub> x ? A)   f ( x )  = \frac { \log x } { \log 11.7 } = \frac { \ln x } { \ln 11.7 }    B)   f ( x )  = \frac { \log 11.7 } { \log x } = \frac { \ln 11.7 } { \ln x }    C) f(x) = log x? + log 11.7 = ln x? + ln 11.7   D)   f ( x )  = \log \frac { 11.7 } { x } = \ln \frac { 11.7 } { x }    E)   f ( x )  = \log \frac { x } { 11.7 } = \ln \frac { x } { 11.7 }  ?
D) f(x) =log11.7x=ln11.7xf ( x ) = \log \frac { 11.7 } { x } = \ln \frac { 11.7 } { x }  Use the change-of-base formula to rewrite the logarithm as a ratio of logarithms.Then use a graphing utility to graph the ratio. ? F(x) = log<sub>11.7</sub> x ? A)   f ( x )  = \frac { \log x } { \log 11.7 } = \frac { \ln x } { \ln 11.7 }    B)   f ( x )  = \frac { \log 11.7 } { \log x } = \frac { \ln 11.7 } { \ln x }    C) f(x) = log x? + log 11.7 = ln x? + ln 11.7   D)   f ( x )  = \log \frac { 11.7 } { x } = \ln \frac { 11.7 } { x }    E)   f ( x )  = \log \frac { x } { 11.7 } = \ln \frac { x } { 11.7 }  ?
E) f(x) =logx11.7=lnx11.7f ( x ) = \log \frac { x } { 11.7 } = \ln \frac { x } { 11.7 } ?  Use the change-of-base formula to rewrite the logarithm as a ratio of logarithms.Then use a graphing utility to graph the ratio. ? F(x) = log<sub>11.7</sub> x ? A)   f ( x )  = \frac { \log x } { \log 11.7 } = \frac { \ln x } { \ln 11.7 }    B)   f ( x )  = \frac { \log 11.7 } { \log x } = \frac { \ln 11.7 } { \ln x }    C) f(x) = log x? + log 11.7 = ln x? + ln 11.7   D)   f ( x )  = \log \frac { 11.7 } { x } = \ln \frac { 11.7 } { x }    E)   f ( x )  = \log \frac { x } { 11.7 } = \ln \frac { x } { 11.7 }  ?

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