Given

f ( x ) = \frac { x ^ { 2 } - 16 } { x + 4 } , g ( x ) = x - 4

.Complete the table and explain how the two functions differ.

\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 6 & - 5.5 & - 5 & - 4.5 & - 4 & - 3.5 & - 3 \\\hline f ( x ) & & & & & & & \\\hline g ( x ) & & & & & & & \\\hline\end{array}

\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 6 & - 5.5 & - 5 & - 4.5 & - 4 & - 3.5 & - 3 \\\hline f ( x ) & - 10 & - 9.5 & - 9 & - 8.5 & \text { Undefined } & - 7.5 & - 7 \\\hline g ( x ) & - 10 & - 9.5 & - 9 & - 8.5 & - 8 & - 7.5 & - 7 \\\hline\end{array}

The graph of f(x)= g(x)except when x = -4.Because the factor x + 4 canceled,there is a hole in the graph of f(x)when x = -4.
B)

\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 6 & - 5.5 & - 5 & - 4.5 & - 4 & - 3.5 & - 3 \\\hline f ( x ) & - 10 & - 9.5 & - 9 & - 8.5 & - 8 & \text { Undefined } & - 7 \\\hline g ( x ) & - 10 & - 9.5 & - 9 & - 8.5 & - 8 & - 7.5 & - 7 \\\hline\end{array}

The graph of f(x)= g(x)except when x = -3.5.Because the factor x + 4 canceled,there is a hole in the graph of f(x)when x = -3.5.
C)

\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 6 & - 5.5 & - 5 & - 4.5 & - 4 & - 3.5 & - 3 \\\hline f ( x ) & - 10 & - 9.5 & - 9 & \text { Undefined } & - 8 & - 7.5 & - 7 \\\hline g ( x ) & - 10 & - 9.5 & - 9 & - 8.5 & - 8 & - 7.5 & - 7 \\\hline\end{array}

The graph of f(x)= g(x)except when x = -4.5.Because the factor x + 4 canceled,there is a hole in the graph of f(x)when x = -4.5.
D)

\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 6 & - 5.5 & - 5 & - 4.5 & - 4 & - 3.5 & - 3 \\\hline f ( x ) & - 10 & - 9.5 & \text { Undefined } & - 8.5 & - 8 & - 7.5 & - 7 \\\hline g ( x ) & - 10 & - 9.5 & - 9 & - 8.5 & - 8 & - 7.5 & - 7 \\\hline\end{array}

The graph of f(x)= g(x)except when x = -5.Because the factor x + 4 canceled,there is a hole in the graph of f(x)when x = -5.
E)

\begin{array} { | c | c | c | c | c | c | c | c | } \hline x & - 6 & - 5.5 & - 5 & - 4.5 & - 4 & - 3.5 & - 3 \\\hline f ( x ) & - 10 & \text { Undefined } & - 9 & - 8.5 & - 8 & - 7.5 & - 7 \\\hline g ( x ) & - 10 & - 9.5 & - 9 & - 8.5 & - 8 & - 7.5 & - 7 \\\hline\end{array}

The graph of f(x)= g(x)except when x = -5.5.Because the factor x + 4 canceled,there is a hole in the graph of f(x)when x = -5.5.

Find Domain of the Following Function g(x)=x2−4x2−3x+2g ( x ) = \frac { x ^ { 2 } - 4 } { x ^ { 2 } - 3 x + 2 }g(x)=x2−3x+2x2−4​

Multiple Choice