?Use the graph of the function f to create a table of values for the given points.Then create a second table that can be used to find f^-1. ?? $?Use the graph of the function f to create a table of values for the given points.Then create a second table that can be used to find f<sup>-1</sup>. ?? ? A) \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline y & 1 & 4 & 7 & 9 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 8 \\ \hline \end{array} \end{array} B) \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline y & 1 & 4 & 7 & 8 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\ \hline \end{array} \end{array} C) \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline y & 1 & 4 & 7 & 9 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\ \hline \end{array} \end{array} D) \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\ \hline y & 1 & 4 & 7 & 8 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\ \hline \end{array} \end{array} E) \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\ \hline y & 1 & 4 & 7 & 8 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\ \hline \end{array} \end{array}$ ?
A)

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\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline y & 1 & 4 & 7 & 8 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\\hline\end{array}\end{array}

\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline y & 1 & 4 & 7 & 9 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\\hline\end{array}\end{array}

\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\\hline y & 1 & 4 & 7 & 8 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\\hline\end{array}\end{array}

\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\\hline y & 1 & 4 & 7 & 8 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\\hline\end{array}\end{array}

Use the Functions Given By f(x)=164x−4f ( x ) = \frac { 1 } { 64 } x - 4f(x)=641​x−4

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Use the Functions Given By $f ( x ) = \frac { 1 } { 64 } x - 4$

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