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Find the Zeros of the Function Algebraically f(x)=18x3xf ( x ) = \frac { 1 } { 8 } x ^ { 3 } - x

Question 24

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Find the zeros of the function algebraically.? f(x) =18x3xf ( x ) = \frac { 1 } { 8 } x ^ { 3 } - x ?


A) x=0,8x = 0 , \sqrt { 8 }
B) x=0,8x = 0 , - \sqrt { 8 }
C) x=0,±8x = 0 , \pm 8
D) x=0,±8x = 0 , \pm \sqrt { 8 }
E) x=0,8x = 0,8

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