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Use the Quadratic Formula to Solve For yyx212xy10y222=0x ^ { 2 } - 12 x y - 10 y ^ { 2 } - 22 = 0

Question 12

Multiple Choice

Use the Quadratic Formula to solve for yy .​ x212xy10y222=0x ^ { 2 } - 12 x y - 10 y ^ { 2 } - 22 = 0


A) y=12x±144x2+40(x2+22) 20y = \frac { 12 x \pm \sqrt { 144 x ^ { 2 } + 40 \left( x ^ { 2 } + 22 \right) } } { - 20 }
B) y=12x±144x2+40(x222) 20y = \frac { 12 x \pm \sqrt { 144 x ^ { 2 } + 40 \left( x ^ { 2 } - 22 \right) } } { - 20 }
C) y=12x±144x2+40(x222) 20y = \frac { 12 x \pm \sqrt { 144 x ^ { 2 } + 40 \left( x ^ { 2 } - 22 \right) } } { 20 }
D) y=12x±144x+40(x222) 20y = \frac { 12 x \pm \sqrt { 144 x + 40 \left( x ^ { 2 } - 22 \right) } } { - 20 }
E) y=12x±144x2+40(x2+22) 20y = \frac { 12 x \pm \sqrt { 144 x ^ { 2 } + 40 \left( x ^ { 2 } + 22 \right) } } { 20 }

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