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Find the Standard Form of the Equation of the Hyperbola (±4,0)( \pm 4,0 )

Question 13

Multiple Choice

Find the standard form of the equation of the hyperbola with the given characteristics and center at the origin. ​
Vertices: (±4,0) ( \pm 4,0 ) ;foci: (±8,0) ( \pm 8,0 )


A) y248x216=1\frac { y ^ { 2 } } { 48 } - \frac { x ^ { 2 } } { 16 } = 1
B) y216x248=1\frac { y ^ { 2 } } { 16 } - \frac { x ^ { 2 } } { 48 } = 1
C) x216y248=1\frac { x ^ { 2 } } { 16 } - \frac { y ^ { 2 } } { 48 } = 1
D) y216+x248=1\frac { y ^ { 2 } } { 16 } + \frac { x ^ { 2 } } { 48 } = 1
E) x216+y248=1\frac { x ^ { 2 } } { 16 } + \frac { y ^ { 2 } } { 48 } = 1

Correct Answer:

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