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Find the Standard Form of the Equation of the Parabola y2=16xy ^ { 2 } = - 16 x

Question 36

Multiple Choice

Find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin. ​
Directrix: x = -4


A) y2=16xy ^ { 2 } = - 16 x
B) y2=16xy ^ { 2 } = 16 x
C) x2=16yx ^ { 2 } = - 16 y
D) x2=16yx ^ { 2 } = 16 y
E) y2=x16y ^ { 2 } = \frac { x } { 16 }

Correct Answer:

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