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Find the Vertex,focus,and Directrix of the Parabola (x+5)2=4(y52)( x + 5 ) ^ { 2 } = 4 \left( y - \frac { 5 } { 2 } \right)

Question 98

Multiple Choice

Find the vertex,focus,and directrix of the parabola.​ (x+5) 2=4(y52) ( x + 5 ) ^ { 2 } = 4 \left( y - \frac { 5 } { 2 } \right)


A) Vertex: (5,52) \left( - 5 , \frac { 5 } { 2 } \right) ;Focus: (5,72) \left( - 5 , \frac { 7 } { 2 } \right) ;Directrix: y=32y = \frac { 3 } { 2 }
B) Vertex: (52,5) \left( \frac { 5 } { 2 } , - 5 \right) ;Focus: (5,32) \left( - 5 , \frac { 3 } { 2 } \right) ;Directrix: y=32y = \frac { 3 } { 2 }
C) Vertex: (52,5) \left( \frac { 5 } { 2 } , - 5 \right) ;Focus: (5,72) \left( - 5 , \frac { 7 } { 2 } \right) ;Directrix: y=32y = \frac { 3 } { 2 }
D) Vertex: (5,52) \left( - 5 , \frac { 5 } { 2 } \right) ;Focus: (5,32) \left( - 5 , \frac { 3 } { 2 } \right) ;Directrix: y=72y = \frac { 7 } { 2 }
E) Vertex: (0,0) ( 0,0 ) ;Focus: (5,72) \left( - 5 , \frac { 7 } { 2 } \right) ;Directrix: y=72y = \frac { 7 } { 2 }

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