Select the standard form of the equation of the parabola and determine the coordinates of the focus. $Select the standard form of the equation of the parabola and determine the coordinates of the focus. A) y ^ { 2 } = - \frac { 49 } { 5 } x ;Focus: \left( \frac { 49 } { 20 } , 0 \right) B) y ^ { 2 } = \frac { 49 } { 5 } x ;Focus: \left( \frac { 49 } { 20 } , 0 \right) C) y ^ { 2 } = - \frac { 49 } { 5 } x ;Focus: \left( - \frac { 49 } { 20 } , 0 \right) D) x ^ { 2 } = - \frac { 49 } { 5 } y Focus: \left( \frac { 49 } { 20 } , 0 \right) E) x ^ { 2 } = \frac { 49 } { 5 } y ;Focus: \left( \frac { 49 } { 20 } , 0 \right)$
A)

y ^ { 2 } = - \frac { 49 } { 5 } x

;Focus:

\left( \frac { 49 } { 20 } , 0 \right)

y ^ { 2 } = \frac { 49 } { 5 } x

;Focus:

\left( \frac { 49 } { 20 } , 0 \right)

y ^ { 2 } = - \frac { 49 } { 5 } x

;Focus:

\left( - \frac { 49 } { 20 } , 0 \right)

x ^ { 2 } = - \frac { 49 } { 5 } y

Focus:

\left( \frac { 49 } { 20 } , 0 \right)

x ^ { 2 } = \frac { 49 } { 5 } y

;Focus:

\left( \frac { 49 } { 20 } , 0 \right)

Give the Coordinates of the Circle's Center and It Radius (x−4)2+(y+3)2=1( x - 4 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 1(x−4)2+(y+3)2=1

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Give the Coordinates of the Circle's Center and It Radius $( x - 4 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 1$

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