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When Testing H0 μ\mu 1 - μ\mu 2 = 2,HA μ\mu 1 - μ\mu

Question 22

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When testing H0: μ\mu 1 - μ\mu 2 = 2,HA: μ\mu 1 - μ\mu 2> 2,where When testing H<sub>0</sub>: \mu <sub>1</sub> - \mu <sub>2</sub> = 2,H<sub>A</sub>: \mu <sub>1</sub> - \mu <sub>2</sub>> 2,where <sub>1</sub> = 522, <sub>2</sub> = 516, \sigma <sub>1</sub><sup>2</sup> = 28, \sigma <sub>2</sub><sup>2</sup> = 24,n<sub>1</sub>= 40,n<sub>2</sub> = 30,at \alpha = .01,what can we conclude? A) Fail to reject H<sub>0</sub> B) Reject H<sub>0</sub> 1 = 522, When testing H<sub>0</sub>: \mu <sub>1</sub> - \mu <sub>2</sub> = 2,H<sub>A</sub>: \mu <sub>1</sub> - \mu <sub>2</sub>> 2,where <sub>1</sub> = 522, <sub>2</sub> = 516, \sigma <sub>1</sub><sup>2</sup> = 28, \sigma <sub>2</sub><sup>2</sup> = 24,n<sub>1</sub>= 40,n<sub>2</sub> = 30,at \alpha = .01,what can we conclude? A) Fail to reject H<sub>0</sub> B) Reject H<sub>0</sub> 2 = 516, σ\sigma 12 = 28, σ\sigma 22 = 24,n1= 40,n2 = 30,at α\alpha = .01,what can we conclude?


A) Fail to reject H0
B) Reject H0

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