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With a 90 Percent Confidence Interval for the Difference Between $\alpha$

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With a 90 percent confidence interval for the difference between the proportions of failures in factory 1 and factory 2 where $With a 90 percent confidence interval for the difference between the proportions of failures in factory 1 and factory 2 where 1 = .05, 2 = .04,n1= 500,n2 = 2000 of (-.0076 .0276) can we reject the null hypothesis at \alpha = .10? A) Yes,reject the null hypothesis B) No;we can't reject the null hypothesis$ ₁ = .05, $With a 90 percent confidence interval for the difference between the proportions of failures in factory 1 and factory 2 where 1 = .05, 2 = .04,n1= 500,n2 = 2000 of (-.0076 .0276) can we reject the null hypothesis at \alpha = .10? A) Yes,reject the null hypothesis B) No;we can't reject the null hypothesis$ ₂ = .04,n₁= 500,n₂ = 2000 of (-.0076 .0276) can we reject the null hypothesis at $\alpha$ = .10?

A) Yes,reject the null hypothesis
B) No;we can't reject the null hypothesis

With a 90 Percent Confidence Interval for the Difference Between α\alphaα

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With a 90 Percent Confidence Interval for the Difference Between $\alpha$

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