Use the figure to answer the question.
The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is V_o at an angle $Use the figure to answer the question. The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is Vo at an angle to the horizon. The vertical dashed lines represent equal time interval, -The vertical velocity at point b is: Note: (g = 9.81 m/s2) A)0 B)Vo cos ( \theta )- ½ g (2 \Delta t)2 C)Vo sin ( \theta )- ½ g (2 \Delta t)2 D)Vo sin ( \theta )+ ½ g (2 \Delta t)2 E)Vo cos ( \theta )+ ½ g (2 \Delta t)2$ to the horizon. The vertical dashed lines represent equal time interval, $Use the figure to answer the question. The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is Vo at an angle to the horizon. The vertical dashed lines represent equal time interval, -The vertical velocity at point b is: Note: (g = 9.81 m/s2) A)0 B)Vo cos ( \theta )- ½ g (2 \Delta t)2 C)Vo sin ( \theta )- ½ g (2 \Delta t)2 D)Vo sin ( \theta )+ ½ g (2 \Delta t)2 E)Vo cos ( \theta )+ ½ g (2 \Delta t)2$
$Use the figure to answer the question. The figure represents the parabolic trajectory of a ball going from a to e in Earth gravity but without air resistance. The initial velocity of the ball is Vo at an angle to the horizon. The vertical dashed lines represent equal time interval, -The vertical velocity at point b is: Note: (g = 9.81 m/s2) A)0 B)Vo cos ( \theta )- ½ g (2 \Delta t)2 C)Vo sin ( \theta )- ½ g (2 \Delta t)2 D)Vo sin ( \theta )+ ½ g (2 \Delta t)2 E)Vo cos ( \theta )+ ½ g (2 \Delta t)2$
-The vertical velocity at point b is: Note: (g = 9.81 m/s²)
A)0
B)V_o cos (

\theta

)- ½ g (2

\Delta

t)²
C)V_o sin (

\theta

)- ½ g (2

\Delta

t)²
D)V_o sin (

\theta

)+ ½ g (2

\Delta

t)²
E)V_o cos (

\theta

)+ ½ g (2

\Delta

t)²

The Initial Path of a Rocket Is 30º Above the Horizontal,and

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