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An Object with a Mass of M = 12 ×\times 10-2 N When V = 16

Question 34

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An object with a mass of m = 12.0 g is falling through a resistive fluid in which g is constant.The retarding frictional force due to the fluid is F = bv,where F is the force in newtons,b is a constant,and v is the speed in meters per second.If F = 3.2 ×\times 10-2 N when v = 16.0 m/s,the terminal speed of the object falling through the fluid is


A) 0.12 m/s
B) 59 m/s
C) 0.19 km/s
D) 16.0 m/s
E) None of these is correct.

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