Bernoulli's equation for nonviscous flow can be stated as $Bernoulli's equation for nonviscous flow can be stated as A fluid is flowing through a horizontal tube that changes in cross-sectional area from A1= 0.75 cm2 to A2 = 0.030 cm2. When v1 = 3.5 cm/s, \rho = 1.4 g/cm3,and viscosity is neglected,the difference between pressure P2 at A2 and P1 at A1 is A)54 \times 103 dyn/cm2,with P1 higher. B)59 dyn/cm2,with P2 higher. C)59 dyn/cm2,with P1 higher. D)8.3 \times 102 dyn/cm2,with P2 higher. E)None of these is correct.$ A fluid is flowing through a horizontal tube that changes in cross-sectional area from A₁= 0.75 cm² to A₂ = 0.030 cm². $Bernoulli's equation for nonviscous flow can be stated as A fluid is flowing through a horizontal tube that changes in cross-sectional area from A1= 0.75 cm2 to A2 = 0.030 cm2. When v1 = 3.5 cm/s, \rho = 1.4 g/cm3,and viscosity is neglected,the difference between pressure P2 at A2 and P1 at A1 is A)54 \times 103 dyn/cm2,with P1 higher. B)59 dyn/cm2,with P2 higher. C)59 dyn/cm2,with P1 higher. D)8.3 \times 102 dyn/cm2,with P2 higher. E)None of these is correct.$ When v₁ = 3.5 cm/s,

\rho

= 1.4 g/cm³,and viscosity is neglected,the difference between pressure P₂ at A₂ and P₁ at A₁ is
A)54

\times

10³ dyn/cm²,with P₁ higher.
B)59 dyn/cm²,with P₂ higher.
C)59 dyn/cm²,with P₁ higher.
D)8.3

\times

10² dyn/cm²,with P₂ higher.
E)None of these is correct.

The Force Exerted by a Stationary Liquid on an Inclined

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