In Simple Harmonic Motion,the Displacement X = a Cos $\omega$ T and the Acceleration a = -

Multiple Choice

In simple harmonic motion,the displacement x = A cos $\omega$ t and the acceleration a = - $\omega$ ²x.If A = 0.25 m and the period is 0.32 s,the acceleration when t = 0.12 s is

A) zero
B) +3.9 m/s²
C) -3.9 m/s²
D) +6.8 m/s²
E) -6.8 m/s²