Multiple Choice
In a simple picture of the hydrogen atom,the electron moves in circular orbits around the central proton attracted by the Coulomb force.The lowest (n = 1) energy orbit that is allowed for the electron is at a radius of 5.29 10-11 m and the second (n = 2) lowest allowed orbit is at 4 times this radius.Calculate the magnetic field strength at the proton due to the orbital motion of the electron in the n = 2 state.
A) 0 T
B) 6.3 T
C) 0.39 T
D) 12.5 T
E) None of the above
Correct Answer:

Verified
Correct Answer:
Verified
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