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The Equation Derived by Bohr for the Wavelengths Of λ\lambda Of the Lines in Hydrogen- Like Spectra Is the Of the Lines

Question 104

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The equation derived by Bohr for the wavelengths of λ\lambda of the lines in hydrogen- like spectra is  The equation derived by Bohr for the wavelengths of  \lambda  of the lines in hydrogen- like spectra is   The first member of the Balmer series of hydrogen has  \lambda  = 660 nm.Doubly ionized   is hydrogen-like.The wavelength of the first member of the Balmer series for doubly ionized   is A) 73 nm B) 5.9  \times  10<sup>3</sup> nm C) 150 nm D) 60 nm E) 1.8  \times  10<sup>-3</sup> nm The first member of the Balmer series of hydrogen has λ\lambda = 660 nm.Doubly ionized  The equation derived by Bohr for the wavelengths of  \lambda  of the lines in hydrogen- like spectra is   The first member of the Balmer series of hydrogen has  \lambda  = 660 nm.Doubly ionized   is hydrogen-like.The wavelength of the first member of the Balmer series for doubly ionized   is A) 73 nm B) 5.9  \times  10<sup>3</sup> nm C) 150 nm D) 60 nm E) 1.8  \times  10<sup>-3</sup> nm is hydrogen-like.The wavelength of the first member of the Balmer series for doubly ionized  The equation derived by Bohr for the wavelengths of  \lambda  of the lines in hydrogen- like spectra is   The first member of the Balmer series of hydrogen has  \lambda  = 660 nm.Doubly ionized   is hydrogen-like.The wavelength of the first member of the Balmer series for doubly ionized   is A) 73 nm B) 5.9  \times  10<sup>3</sup> nm C) 150 nm D) 60 nm E) 1.8  \times  10<sup>-3</sup> nm is


A) 73 nm
B) 5.9 ×\times 103 nm
C) 150 nm
D) 60 nm
E) 1.8 ×\times 10-3 nm

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