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In the Previous Problem, Using the Notation uij=u(x,t)u _ { i j } = u ( x , \mathrm { t } )

Question 22

Multiple Choice

In the previous problem, using the notation uij=u(x,t) u _ { i j } = u ( x , \mathrm { t } ) , and letting λ=ck/h\lambda = c k / h , the equation becomes


A) ui,j+1=λ2ui+1,j+(1+2λ2) uij+λui1,juij12u _ { i , j + 1 } = \lambda ^ { 2 } { } _ { u i } + 1 , j + \left( 1 + 2 \lambda ^ { 2 } \right) u _ { i j } + \lambda _ { u i - 1 , j - u i j - 1 } ^ { 2 }
B) ui,j+1=λ2ui+1,j+(12λ2) uij+λui1,juij12u _ { i , j + 1 } = \lambda ^ { 2 } { } _ { u i } + 1 , j + \left( 1 - 2 \lambda ^ { 2 } \right) u _ { i j } + \lambda _ { u i - 1 , j - u i j - 1 } ^ { 2 }
C) ui,j+1=λui+1,j+(1λ) uij+λui1,juij1u _ { i , j + 1 } = \lambda _ { u i + 1 , j } + ( 1 - \lambda ) u _ { i j } + \lambda _ { u i - 1 , j - u i j - 1 }
D) ui,j1=λ2ui+1,j+(1+2λ2) uij+λui1,j+uij12u _ { i , j - 1 } = \lambda ^ { 2 } { } _ { u i } + 1 , j + \left( 1 + 2 \lambda ^ { 2 } \right) u _ { i j } + \lambda _ { u i - 1 , j + u i j - 1 } ^ { 2 }
E) ui,j1=λui+1,j+(12λ) uij+λui1,j+uij1u _ { i , j - 1 } = \lambda _ { u i + 1 , j } + ( 1 - 2 \lambda ) u _ { i j } + \lambda _ { u i - 1 , j + u i j - 1 }

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