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The Solution of the Differential Equation of the Previous Problem θ=cegt/l\theta = c e ^ { - \mathrm { g } t / l }

Question 22

Multiple Choice

The solution of the differential equation of the previous problem is


A) θ=cegt/l\theta = c e ^ { - \mathrm { g } t / l }
B) θ=celt/g\theta = c e ^ { - l t / g }
C) θ=cegt/l\theta = c e ^ { g t / l }
D) θ=c1cos(gt/l) +c2sin(gt/l) \theta = c _ { 1 } \cos ( g t / l ) + c _ { 2 } \sin ( g t / l )
E) θ=c1cos(g/lt) +c2sin(g/lt) \theta = c _ { 1 } \cos ( \sqrt { g / l } t ) + c _ { 2 } \sin ( \sqrt { g / l } t )

Correct Answer:

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