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Tank a Contains 80 Gallons of Water in Which 20 x(t)x ( t )

Question 11

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Tank A contains 80 gallons of water in which 20 pounds of salt has been dissolved. Tank B contains 30 gallons of water in which 5 pounds of salt has been dissolved. A brine mixture with a concentration of 0.5 pounds of salt per gallon of water is pumped into tank A at the rate of 4 gallons per minute. The well-mixed solution is then pumped from tank A to tank B at the rate of 6 gallons per minute. The solution from tank B is also pumped through another pipe into tank A at the rate of 2 gallons per minute, and the solution from tank B is also pumped out of the system at the rate of 4 gallons per minute. The correct differential equations with initial conditions for the amounts, x(t) x ( t ) and y(t) y ( t ) , of salt in tanks A and B, respectively, at time t are


A) dxdt=2x/40+y/5,dydt=x/40y/3,x(0) =20,y(0) =5\frac { d x } { d t } = 2 - x / 40 + y / 5 , \frac { d y } { d t } = x / 40 - y / 3 , x ( 0 ) = 20 , y ( 0 ) = 5
B) dxdt=23x/40+y/15,dydt=3x/40y/5,x(0) =20,y(0) =5\frac { d x } { d t } = 2 - 3 x / 40 + y / 15 , \frac { d y } { d t } = 3 x / 40 - y / 5 , x ( 0 ) = 20 , y ( 0 ) = 5
C) dxdt=43x/40+y/15,dydt=3x/40y/5,x(0) =20,y(0) =5\frac { d x } { d t } = 4 - 3 x / 40 + y / 15 , \frac { d y } { d t } = 3 x / 40 - y / 5 , x ( 0 ) = 20 , y ( 0 ) = 5
D) dxdt=4x/40+y/5,dydt=x/40y/3,x(0) =20,y(0) =5\frac { d x } { d t } = 4 - x / 40 + y / 5 , \frac { d y } { d t } = x / 40 - y / 3 , x ( 0 ) = 20 , y ( 0 ) = 5
E) dxdt=23x/40+y/5,dydt=x/40y/5,x(0) =20,y(0) =5\frac { d x } { d t } = 2 - 3 x / 40 + y / 5 , \frac { d y } { d t } = x / 40 - y / 5 , x ( 0 ) = 20 , y ( 0 ) = 5

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