Solved

Evaluate the Surface Integral z2+y2=1z ^ { 2 } + y ^ { 2 } = 1

Question 56

Short Answer

Evaluate the surface integral. S is the part of the cylinder z2+y2=1z ^ { 2 } + y ^ { 2 } = 1 between the planes x=0x = 0 and x=1x = 1 in the first octant. S4(x2y+z)dS\iint _ { S } 4 \left( x ^ { 2 } y + z \right) d S

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions