Find the Volume of the Solid Bounded by the Surface $z = x \sqrt { 3 x ^ { 2 } + 3 y }$

Short Answer

Find the volume of the solid bounded by the surface $z = x \sqrt { 3 x ^ { 2 } + 3 y }$ and the planes $x = 1 , x = 0 , y = 1 , y = 0$ , and $z = 0$ . Round your answer to two decimal places.