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Find an Equation of the Hyperbola with Vertices (0,±6)( 0 , \pm 6 )

Question 34

Multiple Choice

Find an equation of the hyperbola with vertices (0,±6) ( 0 , \pm 6 ) and asymptotes y=±x3y = \pm \frac { x } { 3 } .


A) y236x2324=1\frac { y ^ { 2 } } { 36 } - \frac { x ^ { 2 } } { 324 } = 1
B) y236x29=1\frac { y ^ { 2 } } { 36 } - \frac { x ^ { 2 } } { 9 } = 1
C) y2324x236=1\frac { y ^ { 2 } } { 324 } - \frac { x ^ { 2 } } { 36 } = 1
D) x26y29=1\frac { x ^ { 2 } } { 6 } - \frac { y ^ { 2 } } { 9 } = 1
E) x29y236=1\frac { x ^ { 2 } } { 9 } - \frac { y ^ { 2 } } { 36 } = 1

Correct Answer:

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