A Steady Wind Blows a Kite Due West $x=0$ To $x=50$ Ft Is Given By

Short Answer

A steady wind blows a kite due west. The kite's height above ground from horizontal position $x=0$ to $x=50$ ft is given by $y=100-\frac{1}{50}(x-20)^{2}$ .
Find the distance traveled by the kite.
Give your answer rounded to two decimal places.