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The Base of S Is a Circular Region with Boundary 6x2+6y2=246 x^{2}+6 y^{2}=24

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The base of S is a circular region with boundary curve 6x2+6y2=246 x^{2}+6 y^{2}=24 Cross-sections perpendicular to the x axis are isosceles right triangles with hypotenuse in the base.
Find the volume of S.

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