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    Mathematics
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    Calculus Early Transcendentals
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    Exam 4: Integrals
  5. Question
    Find the Critical Numbers of the Function\(y=\frac{x}{x^{2}+36}\)
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Find the Critical Numbers of the Function y=xx2+36y=\frac{x}{x^{2}+36}y=x2+36x​

Question 137

Question 137

Short Answer

Find the critical numbers of the function. y=xx2+36y=\frac{x}{x^{2}+36}y=x2+36x​

Correct Answer:

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