Two Chemicals React to Form Another Chemical $x(t)=\frac{11\left[1-\left(\frac{2}{3}\right)^{3 t}\right]}{1-\frac{1}{4}\left(\frac{2}{3}\right)^{3 t}}$ Where $x(t)$

Short Answer

Two chemicals react to form another chemical. Suppose that the amount of chemical formed in time t (in hours) is given by $x(t)=\frac{11\left[1-\left(\frac{2}{3}\right)^{3 t}\right]}{1-\frac{1}{4}\left(\frac{2}{3}\right)^{3 t}}$ where $x(t)$ is measured in pounds.
a. Find the rate at which the chemical is formed when $t=4$ Round to two decimal places.
b. How many pounds of the chemical are formed eventually?