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    Mathematics
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    Calculus Early Transcendentals
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    Exam 3: Applications of Differentiation
  5. Question
    Find an Equation of the Tangent Line to the Curve\(y=\frac{\sqrt{x}}{x+6} \text { at }(4,0.6)\)
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Find an Equation of the Tangent Line to the Curve y=xx+6 at (4,0.6)y=\frac{\sqrt{x}}{x+6} \text { at }(4,0.6)y=x+6x​​ at (4,0.6)

Question 74

Question 74

Short Answer

Find an equation of the tangent line to the curve. y=xx+6 at (4,0.6)y=\frac{\sqrt{x}}{x+6} \text { at }(4,0.6)y=x+6x​​ at (4,0.6)

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