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  2. Topic
    Mathematics
  3. Study Set
    Calculus Early Transcendentals
  4. Exam
    Exam 3: Applications of Differentiation
  5. Question
    Find the Derivative of the Function\(f(x)=0.001 x^{3}-0.02 x^{2}+0.5 x-0.3 e^{x}+40\)
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Find the Derivative of the Function f(x)=0.001x3−0.02x2+0.5x−0.3ex+40f(x)=0.001 x^{3}-0.02 x^{2}+0.5 x-0.3 e^{x}+40f(x)=0.001x3−0.02x2+0.5x−0.3ex+40

Question 125

Question 125

Short Answer

Find the derivative of the function. f(x)=0.001x3−0.02x2+0.5x−0.3ex+40f(x)=0.001 x^{3}-0.02 x^{2}+0.5 x-0.3 e^{x}+40f(x)=0.001x3−0.02x2+0.5x−0.3ex+40

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