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The Following Frequency Table Summarizes the Ages of 60 Shoppers

Question 18

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The following frequency table summarizes the ages of 60 shoppers at the local farmer's market. The following frequency table summarizes the ages of 60 shoppers at the local farmer's market.   The estimated mean is 36.25,and the estimated standard deviation is 13.57.Calculate the value of the chi-square test statistic to determine whether these measurements came from a normal population.   χ<sup>2</sup> = (10 − .24)<sup>2</sup>/.24 + (21 − 22.458)<sup>2</sup>/22.458 + (10 − 15.51)<sup>2</sup>/15.51 + (8 − 12.27)<sup>2</sup>/12.27 + (5 − 6.732)<sup>2</sup>/6.732 + (6 − 2.79)<sup>2</sup>/2.79 = 404.58 The estimated mean is 36.25,and the estimated standard deviation is 13.57.Calculate the value of the chi-square test statistic to determine whether these measurements came from a normal population. The following frequency table summarizes the ages of 60 shoppers at the local farmer's market.   The estimated mean is 36.25,and the estimated standard deviation is 13.57.Calculate the value of the chi-square test statistic to determine whether these measurements came from a normal population.   χ<sup>2</sup> = (10 − .24)<sup>2</sup>/.24 + (21 − 22.458)<sup>2</sup>/22.458 + (10 − 15.51)<sup>2</sup>/15.51 + (8 − 12.27)<sup>2</sup>/12.27 + (5 − 6.732)<sup>2</sup>/6.732 + (6 − 2.79)<sup>2</sup>/2.79 = 404.58 χ2 = (10 − .24)2/.24 + (21 − 22.458)2/22.458 + (10 − 15.51)2/15.51 + (8 − 12.27)2/12.27
+ (5 − 6.732)2/6.732 + (6 − 2.79)2/2.79 = 404.58

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