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Find a 95 Percent Confidence Interval for the Difference Between

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Find a 95 percent confidence interval for the difference between means,where n1 = 50,n2 = 36,
Find a 95 percent confidence interval for the difference between means,where n<sub>1</sub> = 50,n<sub>2</sub> = 36, = 80, = 75,s<sub>1</sub><sup>2</sup> = 5,and s<sub>2</sub><sup>2</sup> = 3.Assume unequal variances.= 80,
Find a 95 percent confidence interval for the difference between means,where n<sub>1</sub> = 50,n<sub>2</sub> = 36, = 80, = 75,s<sub>1</sub><sup>2</sup> = 5,and s<sub>2</sub><sup>2</sup> = 3.Assume unequal variances.= 75,s12 = 5,and s22 = 3.Assume unequal variances.

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[4.14,5.85]
df = (5/50 + 3/36)...

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