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Find a 99 Percent Confidence Interval for the Difference Between

Question 52

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Find a 99 percent confidence interval for the difference between means,given that n1 = 49,n2 = 49,
Find a 99 percent confidence interval for the difference between means,given that n<sub>1</sub> = 49,n<sub>2</sub> = 49, = 87, = 92,s<sub>1</sub><sup>2</sup> = 13,and s<sub>2</sub><sup>2</sup> = 15.(Assume unequal variances. )= 87,
Find a 99 percent confidence interval for the difference between means,given that n<sub>1</sub> = 49,n<sub>2</sub> = 49, = 87, = 92,s<sub>1</sub><sup>2</sup> = 13,and s<sub>2</sub><sup>2</sup> = 15.(Assume unequal variances. )= 92,s12 = 13,and s22 = 15.(Assume unequal variances. )

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[−6.99,−3.01]
df = (13/49 + 15...

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