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Show That log(x+1x)=log(x+1+x)- \log ( \sqrt { x + 1 } - \sqrt { x } ) = \log ( \sqrt { x + 1 } + \sqrt { x } )

Question 9

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Show that log(x+1x)=log(x+1+x)- \log ( \sqrt { x + 1 } - \sqrt { x } ) = \log ( \sqrt { x + 1 } + \sqrt { x } ) . 

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