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Let p(x)=x4−10x3+37x2−60x+36p ( x ) = x ^ { 4 } - 10 x ^ { 3 } + 37 x ^ { 2 } - 60 x + 36

Question 46

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Let p(x)=x4−10x3+37x2−60x+36p ( x ) = x ^ { 4 } - 10 x ^ { 3 } + 37 x ^ { 2 } - 60 x + 36 . Show that p(2)=0p ( 2 ) = 0 , and p(3)=0p ( 3 ) = 0 . Use this fact to find all the zeros of p(x)p ( x ) .

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Substituting, we see that blured image and...

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