A Titration of 200$\times$ 10 - 5 ,K a2 = 3$\times$ 10 - 9

The Answer of A Titration of 200$\times$ 10 - 5 ,K a2 = 3$\times$ 10 - 9

A Titration of 200$\times$ 10 - 5 ,K a2 = 3$\times$ 10 - 9

The Answer of A Titration of 200$\times$ 10 - 5 ,K a2 = 3$\times$ 10 - 9

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A Titration of 200 $\times$ 10^-⁵,K_a2 = 3 $\times$ 10^-⁹

Question 77

Multiple Choice

A titration of 200.0 mL of 1.32 M H₂A was done with 1.00 M NaOH.For the diprotic acid H₂A,K_a1 = 2.5 $\times$ 10^-⁵,K_a2 = 3.1 $\times$ 10^-⁹.Calculate the pH before any 1.00 M NaOH has been added.

A) 11.76
B) 4.48
C) 9.52
D) 8.96
E) 2.24

A Titration of 200 ×\times× 10-5,Ka2 = 3 ×\times× 10-9

Multiple Choice

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A Titration of 200 $\times$ 10^-⁵,K_a2 = 3 $\times$ 10^-⁹

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